|
In celestial mechanics, the true anomaly is an angular parameter that defines the position of a body moving along a Keplerian orbit. It is the angle between the direction of periapsis and the current position of the body, as seen from the main focus of the ellipse (the point around which the object orbits). The true anomaly is usually denoted by the Greek letters ν or θ, or the Roman letter f. The true anomaly is one of three angular parameters ("anomalies") that define a position along an orbit; the other two being the eccentric anomaly and the mean anomaly. FormulasFrom Wikipedia under the
GNU Free Documentation License From Yahoo Image Search: "True anomaly"  noconsensus.wordpress.com Jeff Id Sun, 28 Mar 2010 14:28:21 GM fitline[,i]=coes[13]*time2+coes[i] } . anomaly. =rep(NA,len) for(i in 1:len) { residual[i]=dat[i]-fitline[i,month[i]] } . anomaly. = residual+time2*coes[13]-mean(time2*coes[13],na.rm=. TRUE. ) list(coes,residual,. anomaly. ) } ### plot average ... From Google Blog Search: "True anomaly"  video.google.com Tue, 20 Jun 2006 22:15:30 PDT Couric he handles it. beautifully. he is just -- HE'S a piece of work. HE'S an anomaly in broadcast. >> Charlie: do you think that ... video.google.com.  youtube.com Wed, 10 Feb 2010 19:37:24 PST The Pipettes - Dirty Mind (First video of the polka dot girls) If you love The Pipettes, go and take a look to my posts on my website for download ... youtube.com.  youtube.com Fri, 08 May 2009 13:58:56 PDT the actual discovery of the anomaly itself for attention is the fact that i have sought out any record or case of this particular anomaly being ... youtube.com. From Google Video Search: "True anomaly"  spacefellowship.com Wed, 25 Aug 2010 06:58:35 GMT+00:00 Space Fellowship The telecom system has been performing without anomaly and is matching predicted performance levels. Kepler is the first mission that uses Ka-Band to ...  spamfighter.com Tue, 31 Aug 2010 04:19:57 GMT+00:00 SPAMfighter News In reality, Telstra did not send that scam e-mail and the claim that an anomaly existed in certain payment wasn't true as well. ...  buffalorumblings.com Tue, 17 Aug 2010 17:10:40 GMT+00:00 Buffalo Rumblings (blog) More photos Alex Brandon - AP The defense of the Buffalo Bills was a statistical anomaly in 2009. Despite giving up over 340 yards and 20 points per game, ... From Google News Search: "True anomaly" Can you find the mean anomaly? Q. At a certain moment, an asteroid is at this position in heliocentric ecliptic coordinates: x = +0.9989289 y = -0.1130118 z = 0 The true anomaly of this point in the orbit is 4.3266930 radians. The asteroid's orbit has a semimajor axis of 1.319533 AU and an eccentricity of 0.6519092. Find the mean anomaly. Asked by David S - Sun Jul 23 17:09:29 2006 - - 2 Answers - 12 Comments A. Just in time for breakfast! First you've got to find the eccentric anomaly. It's about 5.0902029 radians. Then it's a straightforward application of Kepler's equation. The mean anomaly is 5.6961351 radians. Answered by jenab6 - Sun Jul 23 18:35:49 2006 Halley s Comet has a period of 75.32 years and perihelion passage was in Feb. 9, 1986 at a distance of 0.586AU? Q. (a) Determine the semi-major axis of its orbit. (b) Determine the aphelion distance. (c) What is the eccentricity of the comet's orbit? (d) Determine the distance between the comet and the sun for a true anomaly of 165 Asked by mat - Mon Feb 9 00:40:10 2009 - - 1 Answers - 0 Comments A. (a) a = [ mu * P^2 / (4*pi^2) ]^(1/3) a is semi-major axis mu is gravitational parameter of the sun: 39.4 AU^3/yr^2 P is period, 75.32 yr a = 17.83 AU (b) Ra = 2a - Rp Ra is aphelion distance Rp is perihelion distance, 0.586 AU Ra = 2(17.83 AU) - 0.586 AU = 35.07 AU (c) e = 1 - Rp/a e is eccentricity e = 1 - 0.586/17.83 = 0.967 (d) r = Rp(1 + e) / (1 + e*cos(theta)) r is general radius (distance at specified theta angle) theta is the true anomaly angle r(165deg) = 1.751 AU Answered by blueSun - Thu Feb 12 11:08:08 2009 An asteroid is in an orbit with a=2.3 AU, e=0.25, M=45 deg. Can you figure out these quantities?
Q. Here's an easy orbit question. An asteroid is in an orbit with a semimajor axis of 2.3 AU and an eccentricity of 0.25. It's mean anomaly is currently 45 degrees. Calculate: 1. Its period in days 2. Its perihelion distance in AU 3. Its aphelion distance in AU 4. Its orbital angular momentum per unit mass in MKS units 5. Its eccentric anomaly in degrees 6. Its true anomaly in degrees 7. Its current speed relative to the sun in meters per second Ding! Times up! Here are the answers. 1. Its period in days. answer: P = 2.3^1.5 = 3.488 years = 1274 days 2. Its perihelion distance. answer: q = a(1-e) = 1.725 AU 3. Its aphelion distance. answer: p = a(1+e) = 2.875 AU 4. Its orbital angular momentum per unit mass. answer: GM = 1.32712440018E2 [cont.] Asked by Dump the liberals into Jupiter - Sat Nov 22 01:23:55 2008 - - 4 Answers - 1 Comments A. 1. 1,274.04 DAYS 2. 1.725 AU 3. 23.575 AU (that seems way too large, I'l have to double check that, perhaps my math is suffering... not unusual) 4-6 I have never even been exposed to these calculations/formulas, sorry. 7. I suspect I need to know how to figure out 4-6 to get this answer. Answered by DLM - Sat Nov 22 02:57:17 2008 From Yahoo Answer Search: "True anomaly" |
